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SOLUTION 1 = = 0 (The numerator is always 100 and the denominator approaches as x approaches , so that the resulting fraction approaches 0) Click HERE to return to the list of problems SOLUTION 2 = = 0 (The numerator is always 7 and the denominator approaches as x approaches , so that the resulting fraction approaches 0) Click HERE to return to the list of.

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âx2 ynHxL = eynHxL The solutions of this equation are plane waves ynHxL = AexpHäkn xL (68) The eigenenergy en is en = (69) Ñ2 k n 2 2 m For a 1D system with length L and periodic boundary conditions, ynHxL = ynHx LL, we know that the wavevector (momentum) is quantized kn L = 2 np (610) with n being an integer, n = , 2, 1, 0, 1, 2, Or say, kn = 2 n (611) p L. E e e e Axiom 3 Continuity Let x 0. ,Œ AÑ’Å£P ½Öˆœ ÆãΦ ³Ö 9­Ã þø‡K!.

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