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I B a µ π = (48) Example 5 Nonuniform current density Consider an infinitely long, cylindrical conductor of radius R carrying a current I with a nonuniform current density J=br (51) where b is a constant Find the magnetic field everywhere Solution The problem can be solved by using the Ampere’s law ∫Bs⋅=dµ0Ienc GG v (52). €‚Ðèeight="1em"> € (2)é Ètherãases, €`îame‚y€asettlor‚Øôestat€`inƒ ated ñ ‰trust„€„ còecordƒÿƒÿƒÿ>00,ã. " # $ % & ' _init ()V Code LineNumberTable LocalVariableTable this #Lbug1168.

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Ruhanna prepares for her father's arrival on a rare visit from the capital When everything goes terribly wrong, she discovers a mysterious gift that could save her if it doesn't kill her first This short story is part of the world of Nardva, occurring many years before the events of Heart of the Mountain and Akrad's Children oPxY EN. P d µ Ù ifû0°3ufåg fï Æ è ¥fû p d µfÜfúfåg fö fÔg fÛf¹ >Ý>à >Ý>å >Þ>Ý >ß>ß>Þ >ß>á>Ý >ß>ã>Ý 4Ä!lfÿh h fóföfÔg h hzh !lh g föfÔg h fþh 7uføfçh )r !lfÿh h h !l 6!lf÷ g!lfég f¹ g È å ¥ È Ì&k () í ö 0£ #ì8 gugdg2g / d g gdgogug1g0 gfgug fïg g g. òÖ > ú® @ h B D ’ F S H !ì J ) L 1¾ N 9a P A R HÊ T Pm V X@ X ^ì Z `‹ \ `Œ ^ a„ ` eŒ b eœ d f f gp h hp j k l pt n p˜ p p¼ r pè t ƒà v ƒè x.

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For infinite wire use Ampere’s Law ∫Bs⋅=dIµ0 enc GG v ⇒⋅BD2π =µ0I 0 2 I B D µ π = and ˆ 2 D rd= sr⊥ G 0 2 ˆ 4 Id B r µ π × ==∫∫ sr G 00() 442 I I r rr µ µ π π ==0 2 I D µ. I B r µ θ θ π =− (11) where θ12 and θare the angles shown above So, to find the magnetic field at O, we can use the above formula We let point P to be the origin, and θ2 be the angle nearer to the xaxis The problem can be divided into 3 parts. Oracle_Provi_1_TKÛ‡TKÛˆBOOKMOBI ' “ è0x 8~ >† C· Hó N Rþ Xé _à g m— t y# € ‡ Œú “ "™`$Ÿe&¤µ(© *¯D,´7ºY0À 2Å4É 6η8ÓÎØê L > $ @ " B ' D ¤ F '@ H Ö J 52 L ;Ù N B P IL R P T UÓ V X _ˆ Z e“ \ k ^ pØ ` wÈ b }$ d ‚ø f Š h ä j —Ð l º n ¢é p ¨« r ¯ t.

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