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In this example, both coefficients T and R equal ½, so you may reduce the equations to a single expression for the residual commonmode signal, z, induced on either trace by the singleresistor endterminator z(t)=½(x(t)–x(t–Δt)). ZT = ½ (Z PT Z STZPS) (3) where ZP = primary winding impedance ZS = secondary winding impedance ZT = tertiary winding impedance The leakage impedances of the 3winding transformer can also be calculated as follows ZPS = Z P Z S (4) ZPT = Z P Z T (5) ZST = Z S ZT (6) Important In equations (1) to (6), the formulae are vector addition. ^ )z_)t ½)t Z 555 555 ^ T _ ½ ^ )z_ t ½ t Z 555 555 ¼5Å ¼5Å ¼ ¼5¾ ¼ z R 5DQN;&ÔÊø,øô Ôí&ø 555 Nø ÔY 2, KNøô îY 2, ø&&Rø&øîY 2, 'D\V 2K z Ô Z2K î2K^YøZ 2K6z R 6 121( ¼ &2817 ¼5½ 5ÅÊ5ÅÊ5¾Î¾ 680 ¼5Ä 5ÅÌ¿ÃÊ5ÅÌ¿½Ê5¾Ì½ÁÎÂÀ5¾ $9* ¼5½ ÂÀ5¾Í¾Î¿¾5½ R KNøô.
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